4+2(x-3)=3-8(x-8)

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Solution for 4+2(x-3)=3-8(x-8) equation: 



4+2(x-3)=3-8(x-8)

We move all terms to the left:

4+2(x-3)-(3-8(x-8))=0

We multiply parentheses

2x-(3-8(x-8))-6+4=0



We calculate terms in parentheses: -(3-8(x-8)), so:

3-8(x-8)

determiningTheFunctionDomain
-8(x-8)+3

We multiply parentheses

-8x+64+3

We add all the numbers together, and all the variables

-8x+67

Back to the equation:

-(-8x+67)



We add all the numbers together, and all the variables

2x-(-8x+67)-2=0

We get rid of parentheses

2x+8x-67-2=0

We add all the numbers together, and all the variables

10x-69=0

We move all terms containing x to the left, all other terms to the right

10x=69

x=69/10

x=6+9/10

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