3(3y-1)=4(3+y)

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Solution for 3(3y-1)=4(3+y) equation: 



3(3y-1)=4(3+y)

We move all terms to the left:

3(3y-1)-(4(3+y))=0

We add all the numbers together, and all the variables

3(3y-1)-(4(y+3))=0

We multiply parentheses

9y-(4(y+3))-3=0



We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We get rid of parentheses

9y-4y-12-3=0

We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3

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