20=10(2+c)

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Solution for 20=10(2+c) equation: 



20=10(2+c)

We move all terms to the left:

20-(10(2+c))=0

We add all the numbers together, and all the variables

-(10(c+2))+20=0



We calculate terms in parentheses: -(10(c+2)), so:

10(c+2)

We multiply parentheses

10c+20

Back to the equation:

-(10c+20)



We get rid of parentheses

-10c-20+20=0

We add all the numbers together, and all the variables

-10c=0

c=0/-10

c=0

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