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4+1/2x=3/2x-2x
We move all terms to the left:
4+1/2x-(3/2x-2x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x-2x)!=0We add all the numbers together, and all the variables
x∈R
1/2x-(-2x+3/2x)+4=0
We get rid of parentheses
1/2x+2x-3/2x+4=0
We multiply all the terms by the denominator
2x*2x+4*2x+1-3=0
We add all the numbers together, and all the variables
2x*2x+4*2x-2=0
Wy multiply elements
4x^2+8x-2=0
a = 4; b = 8; c = -2;
Δ = b2-4ac
Δ = 82-4·4·(-2)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{6}}{2*4}=\frac{-8-4\sqrt{6}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{6}}{2*4}=\frac{-8+4\sqrt{6}}{8} $
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