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-22+5v=-6-3(v-2)
We move all terms to the left:
-22+5v-(-6-3(v-2))=0
We calculate terms in parentheses: -(-6-3(v-2)), so:We get rid of parentheses
-6-3(v-2)
determiningTheFunctionDomain -3(v-2)-6
We multiply parentheses
-3v+6-6
We add all the numbers together, and all the variables
-3v
Back to the equation:
-(-3v)
5v+3v-22=0
We add all the numbers together, and all the variables
8v-22=0
We move all terms containing v to the left, all other terms to the right
8v=22
v=22/8
v=2+3/4
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