(20x+5)-8=1+2(25x-3)

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Solution for (20x+5)-8=1+2(25x-3) equation: 



(20x+5)-8=1+2(25x-3)

We move all terms to the left:

(20x+5)-8-(1+2(25x-3))=0

We get rid of parentheses

20x-(1+2(25x-3))+5-8=0



We calculate terms in parentheses: -(1+2(25x-3)), so:

1+2(25x-3)

determiningTheFunctionDomain
2(25x-3)+1

We multiply parentheses

50x-6+1

We add all the numbers together, and all the variables

50x-5

Back to the equation:

-(50x-5)



We add all the numbers together, and all the variables

20x-(50x-5)-3=0

We get rid of parentheses

20x-50x+5-3=0

We add all the numbers together, and all the variables

-30x+2=0

We move all terms containing x to the left, all other terms to the right

-30x=-2

x=-2/-30

x=1/15

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