4(y-2)=2(y+1)-5

Solution for 4(y-2)=2(y+1)-5 equation:

4(y-2)=2(y+1)-5

We move all terms to the left:

4(y-2)-(2(y+1)-5)=0

We multiply parentheses

4y-(2(y+1)-5)-8=0


We calculate terms in parentheses: -(2(y+1)-5), so:

2(y+1)-5

We multiply parentheses

2y+2-5

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)


We get rid of parentheses

4y-2y+3-8=0

We add all the numbers together, and all the variables

2y-5=0

We move all terms containing y to the left, all other terms to the right

2y=5

y=5/2

y=2+1/2