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20s^2-17s=63
We move all terms to the left:
20s^2-17s-(63)=0
a = 20; b = -17; c = -63;
Δ = b2-4ac
Δ = -172-4·20·(-63)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-73}{2*20}=\frac{-56}{40} =-1+2/5 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+73}{2*20}=\frac{90}{40} =2+1/4 $
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