0.005(2-k)+0.06(k-5)=1

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Solution for 0.005(2-k)+0.06(k-5)=1 equation: 



0.005(2-k)+0.06(k-5)=1

We move all terms to the left:

0.005(2-k)+0.06(k-5)-(1)=0

We add all the numbers together, and all the variables

0.005(-1k+2)+0.06(k-5)-1=0

We multiply parentheses

-0.005k+0.06k+0.01-0.3-1=0

We add all the numbers together, and all the variables

0.055k-1.29=0

We move all terms containing k to the left, all other terms to the right

0.055k=1.29

k=1.29/0.055

k=23+0.025/0.055

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