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4(y-2)=2(y+1)
We move all terms to the left:
4(y-2)-(2(y+1))=0
We multiply parentheses
4y-(2(y+1))-8=0
We calculate terms in parentheses: -(2(y+1)), so:We get rid of parentheses
2(y+1)
We multiply parentheses
2y+2
Back to the equation:
-(2y+2)
4y-2y-2-8=0
We add all the numbers together, and all the variables
2y-10=0
We move all terms containing y to the left, all other terms to the right
2y=10
y=10/2
y=5
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