2p+1/3(-6p-9)=2(p-1)

Solution for 2p+1/3(-6p-9)=2(p-1) equation:

2p+1/3(-6p-9)=2(p-1)

We move all terms to the left:

2p+1/3(-6p-9)-(2(p-1))=0


Domain of the equation: 3(-6p-9)!=0

p∈R


We multiply all the terms by the denominator


2p*3(-6p-9)-((2(p-1)))*3(-6p-9)+1=0


We calculate terms in parentheses: -((2(p-1)))*3(-6p-9), so:

(2(p-1)))*3(-6p-9

We add all the numbers together, and all the variables

-6p+(2(p-1)))*3(-9

Back to the equation:

-(-6p+(2(p-1)))*3(-9)


Wy multiply elements

6p^2(--(-6p+(2(p-1)))*3(-9)+1=0

We use the square of the difference formula

6p^2(+(-6p+(2(p-1)))*3(-9)+1=0