2(n+1)+4n=2(3n+1)

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Solution for 2(n+1)+4n=2(3n+1) equation: 



2(n+1)+4n=2(3n+1)

We move all terms to the left:

2(n+1)+4n-(2(3n+1))=0

We add all the numbers together, and all the variables

4n+2(n+1)-(2(3n+1))=0

We multiply parentheses

4n+2n-(2(3n+1))+2=0



We calculate terms in parentheses: -(2(3n+1)), so:

2(3n+1)

We multiply parentheses

6n+2

Back to the equation:

-(6n+2)



We add all the numbers together, and all the variables

6n-(6n+2)+2=0

We get rid of parentheses

6n-6n-2+2=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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