4(y-1)=56+12-y

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Solution for 4(y-1)=56+12-y equation: 



4(y-1)=56+12-y

We move all terms to the left:

4(y-1)-(56+12-y)=0

We add all the numbers together, and all the variables

4(y-1)-(-1y+68)=0

We multiply parentheses

4y-(-1y+68)-4=0

We get rid of parentheses

4y+1y-68-4=0

We add all the numbers together, and all the variables

5y-72=0

We move all terms containing y to the left, all other terms to the right

5y=72

y=72/5

y=14+2/5

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