3(2z+1)=33

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Solution for 3(2z+1)=33 equation:



3(2z+1)=33
We move all terms to the left:
3(2z+1)-(33)=0
We multiply parentheses
6z+3-33=0
We add all the numbers together, and all the variables
6z-30=0
We move all terms containing z to the left, all other terms to the right
6z=30
z=30/6
z=5

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