3(w-1)(-w-3)=0

Solution for 3(w-1)(-w-3)=0 equation:

3(w-1)(-w-3)=0

We add all the numbers together, and all the variables

3(w-1)(-1w-3)=0

We multiply parentheses ..

3(-1w^2-3w+w+3)=0

We multiply parentheses

-3w^2-9w+3w+9=0

We add all the numbers together, and all the variables

-3w^2-6w+9=0

a = -3; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·(-3)·9
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-12}{2*-3}=\frac{-6}{-6}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+12}{2*-3}=\frac{18}{-6}
=-3
$