3/5(5r+15)=27

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Solution for 3/5(5r+15)=27 equation: 



3/5(5r+15)=27

We move all terms to the left:

3/5(5r+15)-(27)=0



Domain of the equation: 5(5r+15)!=0

r∈R



We multiply all the terms by the denominator


-27*5(5r+15)+3=0

Wy multiply elements

-135r(5+3=0

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