4(y-1)=4y+2-2(-6y-5)

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Solution for 4(y-1)=4y+2-2(-6y-5) equation: 



4(y-1)=4y+2-2(-6y-5)

We move all terms to the left:

4(y-1)-(4y+2-2(-6y-5))=0

We multiply parentheses

4y-(4y+2-2(-6y-5))-4=0



We calculate terms in parentheses: -(4y+2-2(-6y-5)), so:

4y+2-2(-6y-5)

determiningTheFunctionDomain
4y-2(-6y-5)+2

We multiply parentheses

4y+12y+10+2

We add all the numbers together, and all the variables

16y+12

Back to the equation:

-(16y+12)



We get rid of parentheses

4y-16y-12-4=0

We add all the numbers together, and all the variables

-12y-16=0

We move all terms containing y to the left, all other terms to the right

-12y=16

y=16/-12

y=-1+1/3

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