6v-1+3(2v+5)=-2(v+1)

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Solution for 6v-1+3(2v+5)=-2(v+1) equation: 



6v-1+3(2v+5)=-2(v+1)

We move all terms to the left:

6v-1+3(2v+5)-(-2(v+1))=0

We multiply parentheses

6v+6v-(-2(v+1))+15-1=0



We calculate terms in parentheses: -(-2(v+1)), so:

-2(v+1)

We multiply parentheses

-2v-2

Back to the equation:

-(-2v-2)



We add all the numbers together, and all the variables

12v-(-2v-2)+14=0

We get rid of parentheses

12v+2v+2+14=0

We add all the numbers together, and all the variables

14v+16=0

We move all terms containing v to the left, all other terms to the right

14v=-16

v=-16/14

v=-1+1/7

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