4(x-3)=8x-(4x-12)

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Solution for 4(x-3)=8x-(4x-12) equation: 



4(x-3)=8x-(4x-12)

We move all terms to the left:

4(x-3)-(8x-(4x-12))=0

We multiply parentheses

4x-(8x-(4x-12))-12=0



We calculate terms in parentheses: -(8x-(4x-12)), so:

8x-(4x-12)

We get rid of parentheses

8x-4x+12

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

4x-4x-12-12=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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