v-5+2(4v+4)=-6(v+1)

Solution for v-5+2(4v+4)=-6(v+1) equation:

v-5+2(4v+4)=-6(v+1)

We move all terms to the left:

v-5+2(4v+4)-(-6(v+1))=0

We multiply parentheses

v+8v-(-6(v+1))+8-5=0


We calculate terms in parentheses: -(-6(v+1)), so:

-6(v+1)

We multiply parentheses

-6v-6

Back to the equation:

-(-6v-6)


We add all the numbers together, and all the variables

9v-(-6v-6)+3=0

We get rid of parentheses

9v+6v+6+3=0

We add all the numbers together, and all the variables

15v+9=0

We move all terms containing v to the left, all other terms to the right

15v=-9

v=-9/15

v=-3/5