2u+1-3(-6u-3)=2(u-2)

Solution for 2u+1-3(-6u-3)=2(u-2) equation:

2u+1-3(-6u-3)=2(u-2)

We move all terms to the left:

2u+1-3(-6u-3)-(2(u-2))=0

We multiply parentheses

2u+18u-(2(u-2))+9+1=0


We calculate terms in parentheses: -(2(u-2)), so:

2(u-2)

We multiply parentheses

2u-4

Back to the equation:

-(2u-4)


We add all the numbers together, and all the variables

20u-(2u-4)+10=0

We get rid of parentheses

20u-2u+4+10=0

We add all the numbers together, and all the variables

18u+14=0

We move all terms containing u to the left, all other terms to the right

18u=-14

u=-14/18

u=-7/9