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4(x-3)+8=2x+2(-4+x)
We move all terms to the left:
4(x-3)+8-(2x+2(-4+x))=0
We add all the numbers together, and all the variables
4(x-3)-(2x+2(x-4))+8=0
We multiply parentheses
4x-(2x+2(x-4))-12+8=0
We calculate terms in parentheses: -(2x+2(x-4)), so:We add all the numbers together, and all the variables
2x+2(x-4)
We multiply parentheses
2x+2x-8
We add all the numbers together, and all the variables
4x-8
Back to the equation:
-(4x-8)
4x-(4x-8)-4=0
We get rid of parentheses
4x-4x+8-4=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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