3(x-1)+7=4x-3-2(3-4x)

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Solution for 3(x-1)+7=4x-3-2(3-4x) equation: 



3(x-1)+7=4x-3-2(3-4x)

We move all terms to the left:

3(x-1)+7-(4x-3-2(3-4x))=0

We add all the numbers together, and all the variables

3(x-1)-(4x-3-2(-4x+3))+7=0

We multiply parentheses

3x-(4x-3-2(-4x+3))-3+7=0



We calculate terms in parentheses: -(4x-3-2(-4x+3)), so:

4x-3-2(-4x+3)

determiningTheFunctionDomain
4x-2(-4x+3)-3

We multiply parentheses

4x+8x-6-3

We add all the numbers together, and all the variables

12x-9

Back to the equation:

-(12x-9)



We add all the numbers together, and all the variables

3x-(12x-9)+4=0

We get rid of parentheses

3x-12x+9+4=0

We add all the numbers together, and all the variables

-9x+13=0

We move all terms containing x to the left, all other terms to the right

-9x=-13

x=-13/-9

x=1+4/9

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