(-3-5y+10-y=-2)

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Solution for (-3-5y+10-y=-2) equation: 



(-3-5y+10-y=-2)

We move all terms to the left:

(-3-5y+10-y-(-2))=0



We calculate terms in parentheses: +(-3-5y+10-y-(-2)), so:

-3-5y+10-y-(-2)

determiningTheFunctionDomain
-5y-y-3+10-(-2)

We add all the numbers together, and all the variables

-6y+9

Back to the equation:

+(-6y+9)



We get rid of parentheses

-6y+9=0

We move all terms containing y to the left, all other terms to the right

-6y=-9

y=-9/-6

y=1+1/2

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