-2(5y-2)+7y=8+2(6y-5)

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Solution for -2(5y-2)+7y=8+2(6y-5) equation: 



-2(5y-2)+7y=8+2(6y-5)

We move all terms to the left:

-2(5y-2)+7y-(8+2(6y-5))=0

We add all the numbers together, and all the variables

7y-2(5y-2)-(8+2(6y-5))=0

We multiply parentheses

7y-10y-(8+2(6y-5))+4=0



We calculate terms in parentheses: -(8+2(6y-5)), so:

8+2(6y-5)

determiningTheFunctionDomain
2(6y-5)+8

We multiply parentheses

12y-10+8

We add all the numbers together, and all the variables

12y-2

Back to the equation:

-(12y-2)



We add all the numbers together, and all the variables

-3y-(12y-2)+4=0

We get rid of parentheses

-3y-12y+2+4=0

We add all the numbers together, and all the variables

-15y+6=0

We move all terms containing y to the left, all other terms to the right

-15y=-6

y=-6/-15

y=2/5

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