4(x-3)+36=64-4(x+2)

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Solution for 4(x-3)+36=64-4(x+2) equation: 



4(x-3)+36=64-4(x+2)

We move all terms to the left:

4(x-3)+36-(64-4(x+2))=0

We multiply parentheses

4x-(64-4(x+2))-12+36=0



We calculate terms in parentheses: -(64-4(x+2)), so:

64-4(x+2)

determiningTheFunctionDomain
-4(x+2)+64

We multiply parentheses

-4x-8+64

We add all the numbers together, and all the variables

-4x+56

Back to the equation:

-(-4x+56)



We add all the numbers together, and all the variables

4x-(-4x+56)+24=0

We get rid of parentheses

4x+4x-56+24=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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