4(x-3)+12=2(3x+5)

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Solution for 4(x-3)+12=2(3x+5) equation: 



4(x-3)+12=2(3x+5)

We move all terms to the left:

4(x-3)+12-(2(3x+5))=0

We multiply parentheses

4x-(2(3x+5))-12+12=0



We calculate terms in parentheses: -(2(3x+5)), so:

2(3x+5)

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We add all the numbers together, and all the variables

4x-(6x+10)=0

We get rid of parentheses

4x-6x-10=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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