127=-2+3(1+6b)

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Solution for 127=-2+3(1+6b) equation: 



127=-2+3(1+6b)

We move all terms to the left:

127-(-2+3(1+6b))=0

We add all the numbers together, and all the variables

-(-2+3(6b+1))+127=0



We calculate terms in parentheses: -(-2+3(6b+1)), so:

-2+3(6b+1)

determiningTheFunctionDomain
3(6b+1)-2

We multiply parentheses

18b+3-2

We add all the numbers together, and all the variables

18b+1

Back to the equation:

-(18b+1)



We get rid of parentheses

-18b-1+127=0

We add all the numbers together, and all the variables

-18b+126=0

We move all terms containing b to the left, all other terms to the right

-18b=-126

b=-126/-18

b=+7

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