2/3(6x-12)=1/4(8x+4)

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Solution for 2/3(6x-12)=1/4(8x+4) equation: 



2/3(6x-12)=1/4(8x+4)

We move all terms to the left:

2/3(6x-12)-(1/4(8x+4))=0



Domain of the equation: 3(6x-12)!=0

x∈R





Domain of the equation: 4(8x+4))!=0

x∈R



We calculate fractions


(8x8/(3(6x-12)*4(8x+4)))+(-3x6/(3(6x-12)*4(8x+4)))=0



We calculate terms in parentheses: +(8x8/(3(6x-12)*4(8x+4))), so:

8x8/(3(6x-12)*4(8x+4))

We multiply all the terms by the denominator


8x8

We add all the numbers together, and all the variables

8x^8

We do not support expression: x^8

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