(6+x+8)(3x+4)=0

Solution for (6+x+8)(3x+4)=0 equation:

(6+x+8)(3x+4)=0

We add all the numbers together, and all the variables

(x+14)(3x+4)=0

We multiply parentheses ..

(+3x^2+4x+42x+56)=0

We get rid of parentheses

3x^2+4x+42x+56=0

We add all the numbers together, and all the variables

3x^2+46x+56=0

a = 3; b = 46; c = +56;
Δ = b2-4ac
Δ = 462-4·3·56
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-38}{2*3}=\frac{-84}{6}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+38}{2*3}=\frac{-8}{6}
=-1+1/3
$