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4(x-2)-2x=2(x+1)
We move all terms to the left:
4(x-2)-2x-(2(x+1))=0
We add all the numbers together, and all the variables
-2x+4(x-2)-(2(x+1))=0
We multiply parentheses
-2x+4x-(2(x+1))-8=0
We calculate terms in parentheses: -(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
2x-(2x+2)-8=0
We get rid of parentheses
2x-2x-2-8=0
We add all the numbers together, and all the variables
-10!=0
There is no solution for this equation
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