-a+(4(-3a+4))=-26+a

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Solution for -a+(4(-3a+4))=-26+a equation: 



-a+(4(-3a+4))=-26+a

We move all terms to the left:

-a+(4(-3a+4))-(-26+a)=0

We add all the numbers together, and all the variables

-a+(4(-3a+4))-(a-26)=0

We add all the numbers together, and all the variables

-1a+(4(-3a+4))-(a-26)=0

We get rid of parentheses

-1a+(4(-3a+4))-a+26=0



We calculate terms in parentheses: +(4(-3a+4)), so:

4(-3a+4)

We multiply parentheses

-12a+16

Back to the equation:

+(-12a+16)



We add all the numbers together, and all the variables

-2a+(-12a+16)+26=0

We get rid of parentheses

-2a-12a+16+26=0

We add all the numbers together, and all the variables

-14a+42=0

We move all terms containing a to the left, all other terms to the right

-14a=-42

a=-42/-14

a=+3

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