20(x+2)-10(x-4)=140

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Solution for 20(x+2)-10(x-4)=140 equation: 



20(x+2)-10(x-4)=140

We move all terms to the left:

20(x+2)-10(x-4)-(140)=0

We multiply parentheses

20x-10x+40+40-140=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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