4(x-2)+3=3x-2(x+3)

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Solution for 4(x-2)+3=3x-2(x+3) equation: 



4(x-2)+3=3x-2(x+3)

We move all terms to the left:

4(x-2)+3-(3x-2(x+3))=0

We multiply parentheses

4x-(3x-2(x+3))-8+3=0



We calculate terms in parentheses: -(3x-2(x+3)), so:

3x-2(x+3)

We multiply parentheses

3x-2x-6

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We add all the numbers together, and all the variables

4x-(x-6)-5=0

We get rid of parentheses

4x-x+6-5=0

We add all the numbers together, and all the variables

3x+1=0

We move all terms containing x to the left, all other terms to the right

3x=-1

x=-1/3

x=-1/3

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