2(k-5)+3k=6+k

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Solution for 2(k-5)+3k=6+k equation: 



2(k-5)+3k=6+k

We move all terms to the left:

2(k-5)+3k-(6+k)=0

We add all the numbers together, and all the variables

2(k-5)+3k-(k+6)=0

We add all the numbers together, and all the variables

3k+2(k-5)-(k+6)=0

We multiply parentheses

3k+2k-(k+6)-10=0

We get rid of parentheses

3k+2k-k-6-10=0

We add all the numbers together, and all the variables

4k-16=0

We move all terms containing k to the left, all other terms to the right

4k=16

k=16/4

k=4

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