1/3x-5=4/6x+3

Solution for 1/3x-5=4/6x+3 equation:

1/3x-5=4/6x+3

We move all terms to the left:

1/3x-5-(4/6x+3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x+3)!=0

x∈R


We get rid of parentheses

1/3x-4/6x-3-5=0

We calculate fractions


6x/18x^2+(-12x)/18x^2-3-5=0

We add all the numbers together, and all the variables

6x/18x^2+(-12x)/18x^2-8=0

We multiply all the terms by the denominator


6x+(-12x)-8*18x^2=0

Wy multiply elements

-144x^2+6x+(-12x)=0

We get rid of parentheses

-144x^2+6x-12x=0

We add all the numbers together, and all the variables

-144x^2-6x=0

a = -144; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-144)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-144}=\frac{0}{-288}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-144}=\frac{12}{-288}
=-1/24
$