4(x-1)+x-3=-2(x+4)+6(x-1)

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Solution for 4(x-1)+x-3=-2(x+4)+6(x-1) equation: 



4(x-1)+x-3=-2(x+4)+6(x-1)

We move all terms to the left:

4(x-1)+x-3-(-2(x+4)+6(x-1))=0

We add all the numbers together, and all the variables

x+4(x-1)-(-2(x+4)+6(x-1))-3=0

We multiply parentheses

x+4x-(-2(x+4)+6(x-1))-4-3=0



We calculate terms in parentheses: -(-2(x+4)+6(x-1)), so:

-2(x+4)+6(x-1)

We multiply parentheses

-2x+6x-8-6

We add all the numbers together, and all the variables

4x-14

Back to the equation:

-(4x-14)



We add all the numbers together, and all the variables

5x-(4x-14)-7=0

We get rid of parentheses

5x-4x+14-7=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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