16-8x+4(x-6)=-(2x-3)+-(x+1)+6

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Solution for 16-8x+4(x-6)=-(2x-3)+-(x+1)+6 equation: 



16-8x+4(x-6)=-(2x-3)+-(x+1)+6

We move all terms to the left:

16-8x+4(x-6)-(-(2x-3)+-(x+1)+6)=0

We use the square of the difference formula

-8x+4(x-6)-(-(2x-3)-(x+1)+6)+16=0

We multiply parentheses

-8x+4x-(-(2x-3)-(x+1)+6)-24+16=0



We calculate terms in parentheses: -(-(2x-3)-(x+1)+6), so:

-(2x-3)-(x+1)+6

We get rid of parentheses

-2x-x+3-1+6

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We add all the numbers together, and all the variables

-4x-(-3x+8)-8=0

We get rid of parentheses

-4x+3x-8-8=0

We add all the numbers together, and all the variables

-1x-16=0

We move all terms containing x to the left, all other terms to the right

-x=16

x=16/-1

x=-16

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