32=8z+4(5+z)

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Solution for 32=8z+4(5+z) equation: 



32=8z+4(5+z)

We move all terms to the left:

32-(8z+4(5+z))=0

We add all the numbers together, and all the variables

-(8z+4(z+5))+32=0



We calculate terms in parentheses: -(8z+4(z+5)), so:

8z+4(z+5)

We multiply parentheses

8z+4z+20

We add all the numbers together, and all the variables

12z+20

Back to the equation:

-(12z+20)



We get rid of parentheses

-12z-20+32=0

We add all the numbers together, and all the variables

-12z+12=0

We move all terms containing z to the left, all other terms to the right

-12z=-12

z=-12/-12

z=1

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