4(x+x2)=240

Solution for 4(x+x2)=240 equation:

4(x+x2)=240

We move all terms to the left:

4(x+x2)-(240)=0

We add all the numbers together, and all the variables

4(+x+x^2)-240=0

We multiply parentheses

4x^2+4x-240=0

a = 4; b = 4; c = -240;
Δ = b2-4ac
Δ = 42-4·4·(-240)
Δ = 3856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3856}=\sqrt{16*241}=\sqrt{16}*\sqrt{241}=4\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{241}}{2*4}=\frac{-4-4\sqrt{241}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{241}}{2*4}=\frac{-4+4\sqrt{241}}{8}
$