7(2b-5)-(6-5b)=41

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Solution for 7(2b-5)-(6-5b)=41 equation: 



7(2b-5)-(6-5b)=41

We move all terms to the left:

7(2b-5)-(6-5b)-(41)=0

We add all the numbers together, and all the variables

7(2b-5)-(-5b+6)-41=0

We multiply parentheses

14b-(-5b+6)-35-41=0

We get rid of parentheses

14b+5b-6-35-41=0

We add all the numbers together, and all the variables

19b-82=0

We move all terms containing b to the left, all other terms to the right

19b=82

b=82/19

b=4+6/19

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