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2/3x=x-12
We move all terms to the left:
2/3x-(x-12)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-x+12=0
We multiply all the terms by the denominator
-x*3x+12*3x+2=0
Wy multiply elements
-3x^2+36x+2=0
a = -3; b = 36; c = +2;
Δ = b2-4ac
Δ = 362-4·(-3)·2
Δ = 1320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1320}=\sqrt{4*330}=\sqrt{4}*\sqrt{330}=2\sqrt{330}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{330}}{2*-3}=\frac{-36-2\sqrt{330}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{330}}{2*-3}=\frac{-36+2\sqrt{330}}{-6} $
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