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4(x+6)3x=25
We move all terms to the left:
4(x+6)3x-(25)=0
We multiply parentheses
12x^2+72x-25=0
a = 12; b = 72; c = -25;
Δ = b2-4ac
Δ = 722-4·12·(-25)
Δ = 6384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6384}=\sqrt{16*399}=\sqrt{16}*\sqrt{399}=4\sqrt{399}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-4\sqrt{399}}{2*12}=\frac{-72-4\sqrt{399}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+4\sqrt{399}}{2*12}=\frac{-72+4\sqrt{399}}{24} $
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