18x2+3x=1

Solution for 18x2+3x=1 equation:

18x^2+3x=1

We move all terms to the left:

18x^2+3x-(1)=0

a = 18; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·18·(-1)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*18}=\frac{-12}{36}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*18}=\frac{6}{36}
=1/6
$