A=3(2x-5)-4(x-3)

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Solution for A=3(2x-5)-4(x-3) equation: 



=3(2A-5)-4(A-3)

We move all terms to the left:

-(3(2A-5)-4(A-3))=0



We calculate terms in parentheses: -(3(2A-5)-4(A-3)), so:

3(2A-5)-4(A-3)

We multiply parentheses

6A-4A-15+12

We add all the numbers together, and all the variables

2A-3

Back to the equation:

-(2A-3)



We get rid of parentheses

-2A+3=0

We move all terms containing A to the left, all other terms to the right

-2A=-3

A=-3/-2

A=1+1/2

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