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4(x+4)-6=2x+2(5+x)
We move all terms to the left:
4(x+4)-6-(2x+2(5+x))=0
We add all the numbers together, and all the variables
4(x+4)-(2x+2(x+5))-6=0
We multiply parentheses
4x-(2x+2(x+5))+16-6=0
We calculate terms in parentheses: -(2x+2(x+5)), so:We add all the numbers together, and all the variables
2x+2(x+5)
We multiply parentheses
2x+2x+10
We add all the numbers together, and all the variables
4x+10
Back to the equation:
-(4x+10)
4x-(4x+10)+10=0
We get rid of parentheses
4x-4x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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