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7x(2x-10)=39
We move all terms to the left:
7x(2x-10)-(39)=0
We multiply parentheses
14x^2-70x-39=0
a = 14; b = -70; c = -39;
Δ = b2-4ac
Δ = -702-4·14·(-39)
Δ = 7084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7084}=\sqrt{4*1771}=\sqrt{4}*\sqrt{1771}=2\sqrt{1771}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1771}}{2*14}=\frac{70-2\sqrt{1771}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1771}}{2*14}=\frac{70+2\sqrt{1771}}{28} $
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