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-5/3(4x+1)+6x=11/3
We move all terms to the left:
-5/3(4x+1)+6x-(11/3)=0
Domain of the equation: 3(4x+1)!=0We add all the numbers together, and all the variables
x∈R
-5/3(4x+1)+6x-(+11/3)=0
We add all the numbers together, and all the variables
6x-5/3(4x+1)-(+11/3)=0
We get rid of parentheses
6x-5/3(4x+1)-11/3=0
We calculate fractions
6x=0
x=0/6
x=0
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