If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4(x+3)=12+x
We move all terms to the left:
4(x+3)-(12+x)=0
We add all the numbers together, and all the variables
4(x+3)-(x+12)=0
We multiply parentheses
4x-(x+12)+12=0
We get rid of parentheses
4x-x-12+12=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
| 4(2y+8)=16 | | 8/5=n/15 | | -16=-4y+2(y-4) | | 16x-30=10x | | 4x(3x-12)+x(3x-12)-10(3x-12)=0 | | 3x+10=7x-11+10 | | 7(2g−5)= | | 3(6k+1)= | | 6(1+2j)= | | 2x+6+14=20 | | 3(1+3j)= | | 3x^2-x-13=(-9) | | 2t+5=3t-8 | | 2x2+3=x2+28 | | 5(3x−4)= | | 6x+15=3x(2x+6) | | 2x+3=5x+7-8x | | 2(4+7d)= | | -36=5x-(-14) | | 5(3x−4)=1 | | 45x=14 | | x-3+12=18 | | X+130=x+62 | | 12/18=54/n | | 2x^2+3=x^2+28 | | (6n+5)(3n+5)=0 | | 3x2-x-13=(-9) | | 35x-50=10x+75 | | 1.25u=40 | | 26x+6=28x-2 | | 5b+10=3b+35 | | 16=5x-9, |