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4x(3x-12)+x(3x-12)-10(3x-12)=0
We multiply parentheses
12x^2+3x^2-48x-12x-30x+120=0
We add all the numbers together, and all the variables
15x^2-90x+120=0
a = 15; b = -90; c = +120;
Δ = b2-4ac
Δ = -902-4·15·120
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-30}{2*15}=\frac{60}{30} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+30}{2*15}=\frac{120}{30} =4 $
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